MATHEMATICS HIPHOP • A-LEVEL PURE MATHEMATICS
CHAPTER 09: POWERS
PART 3: SURDS AND THEIR SIMPLIFICATION
Building exact answers through the correct use of irrational roots.
Learning Objectives
By the end of this lesson, you should be able to:
- Explain what a surd is and distinguish it from a rational root.
- Simplify surds by extracting square factors.
- Add and subtract like surds.
- Multiply and divide expressions involving surds.
- Expand brackets containing surds.
- Use conjugates to rationalise denominators.
- Express exact answers in their simplest surd form.
1. Understanding Surds
A surd is an irrational root expressed exactly in root form. It cannot be simplified to a rational number.
For example, √2, √3 and √5 are surds because their values cannot be expressed exactly as fractions of integers.
Examples of roots that are not surds
√4 = 2
√9 = 3
√25 = 5
These are not surds because their roots are rational integers.
Compare the following:
- √16 = 4 — not a surd.
- √18 = 3√2 — a surd.
- √49 = 7 — not a surd.
- √50 = 5√2 — a surd.
2. Basic Laws of Surds
For non-negative real numbers a and b, the following laws are useful:
Product law
√a × √b = √(ab)
Quotient law
√a ÷ √b = √(a/b), where b is positive.
Square of a surd
(√a)² = a
Important warning: A square root does not distribute over addition or subtraction.
In general:
√(a + b) ≠ √a + √b
For example, √(9 + 16) = √25 = 5, whereas √9 + √16 = 3 + 4 = 7.
3. Simplifying Surds
To simplify a surd, express the number inside the root as a product containing the largest possible perfect-square factor.
Remember that:
√(ab) = √a × √b
Worked Example 1
Simplify √72.
Step 1: Identify a perfect-square factor.
72 = 36 × 2
Step 2: Separate the factors.
√72 = √36 × √2
Step 3: Evaluate the perfect square.
√72 = 6√2
Worked Example 2
Simplify √180.
180 = 36 × 5
√180 = √36 × √5
√180 = 6√5
Worked Example 3
Simplify 3√48.
3√48 = 3√(16 × 3)
= 3 × 4√3
= 12√3
Worked Example 4
Simplify √200 − √32.
√200 = √(100 × 2) = 10√2
√32 = √(16 × 2) = 4√2
Therefore:
√200 − √32 = 10√2 − 4√2
= 6√2
4. Adding and Subtracting Surds
Only like surds can be added or subtracted directly. Like surds have the same root part after simplification.
For example, 3√5 and 7√5 are like surds, but √2 and √3 are unlike surds.
Worked Example 5
Simplify 5√3 + 2√3 − 4√3.
Collect the coefficients:
=(5 + 2 − 4)√3
= 3√3
Worked Example 6
Simplify √12 + √27 − √75.
√12 = 2√3
√27 = 3√3
√75 = 5√3
Therefore:
= 2√3 + 3√3 − 5√3
= 0
Remember: Simplify each surd first. Then collect like terms.
5. Multiplication of Surds
When multiplying surds, multiply the numbers outside the roots and multiply the numbers inside the roots.
√a × √b = √(ab)
Worked Example 7
Simplify √6 × √15.
= √90
= √(9 × 10)
= 3√10
Worked Example 8
Simplify 2√3 × 5√6.
= (2 × 5)(√3 × √6)
= 10√18
= 10 × 3√2
= 30√2
6. Division of Surds
To divide surds, divide the coefficients and simplify the resulting root where possible.
Worked Example 9
Simplify √75 ÷ √3.
= √(75/3)
= √25
= 5
Worked Example 10
Simplify 6√20 ÷ 3√5.
= (6/3) × √(20/5)
= 2 × √4
= 4
7. Expanding Brackets Containing Surds
Surds obey the ordinary laws of algebra. Use the distributive law and collect like terms after expanding.
Worked Example 11
Expand and simplify 3(2 + √5).
= 3 × 2 + 3 × √5
= 6 + 3√5
Worked Example 12
Expand and simplify (2 + √3)(4 + √3).
=(2 × 4) + (2 × √3) + (4 × √3) + (√3 × √3)
= 8 + 2√3 + 4√3 + 3
= 11 + 6√3
Answer: 11 + 6√3
Worked Example 13
Expand and simplify (√5 + 2)(√5 − 2).
=(√5)² − 2√5 + 2√5 − 2²
= 5 − 4
= 1
This is an example of the difference of two squares.
8. Conjugates of Surds
The conjugate of a binomial involving a surd is obtained by changing the sign between its two terms.
For example:
- The conjugate of 3 + √2 is 3 − √2.
- The conjugate of 5 − √7 is 5 + √7.
The important identity is:
(a + b)(a − b) = a² − b²
Conjugates are particularly useful when rationalising denominators.
9. Rationalising a Denominator
Rationalising a denominator means rewriting a fraction so that there is no surd in its denominator.
Case 1: A single surd in the denominator
Worked Example 14
Rationalise 5/√3.
Multiply the numerator and denominator by √3:
= (5/√3) × (√3/√3)
= 5√3/3
Answer: 5√3/3
Case 2: A binomial denominator
When the denominator contains two terms, multiply by its conjugate.
Worked Example 15
Rationalise 4/(2 + √3).
The conjugate of 2 + √3 is 2 − √3.
Multiply the numerator and denominator by this conjugate:
= [4(2 − √3)]/[(2 + √3)(2 − √3)]
= (8 − 4√3)/(4 − 3)
= 8 − 4√3
Worked Example 16
Rationalise 3/(√5 − 1).
The conjugate is √5 + 1.
= [3(√5 + 1)]/[(√5 − 1)(√5 + 1)]
= 3(√5 + 1)/(5 − 1)
= 3(√5 + 1)/4
10. Expressing Answers in the Form a + b√c
Some examination questions require an expression to be written in the form a + b√c, where a and b are rational numbers and c is a positive integer with no square factor greater than 1.
Worked Example 17
Express (2 + √3)/(2 − √3) in the form a + b√3.
Multiply by the conjugate of the denominator:
= [(2 + √3)(2 + √3)]/[(2 − √3)(2 + √3)]
Numerator:
(2 + √3)² = 4 + 4√3 + 3 = 7 + 4√3
Denominator:
4 − 3 = 1
Answer: 7 + 4√3
Hence a = 7 and b = 4.
11. Common Examination Errors
Error 1: Adding unlike surds
Incorrect: √2 + √3 = √5
Correct: √2 + √3 remains √2 + √3.
Error 2: Splitting a root over addition
Incorrect: √(a + b) = √a + √b
There is no such general law.
Error 3: Forgetting to simplify
√48 should be written as 4√3, not left as √48.
Error 4: Multiplying only the denominator when rationalising
Always multiply both numerator and denominator by the same expression.
Error 5: Forgetting the conjugate identity
(a + b)(a − b) = a² − b², not a² + b².
12. Examination Practice
Attempt the following questions before opening the solutions. Give exact answers in their simplest form.
Exercise A: Simplification
- Simplify √108.
- Simplify √245.
- Simplify 4√75.
- Simplify 2√18 + √50.
- Simplify 3√80 − 2√45.
Open worked solutions — Exercise A
1. √108 = √(36 × 3) = 6√3.
2. √245 = √(49 × 5) = 7√5.
3. 4√75 = 4 × 5√3 = 20√3.
4. 2√18 + √50 = 2(3√2) + 5√2 = 11√2.
5. 3√80 − 2√45 = 3(4√5) − 2(3√5) = 6√5.
Exercise B: Operations
- Simplify √12 × √27.
- Simplify 3√5 × 2√10.
- Simplify √147 ÷ √3.
- Expand and simplify (3 + √2)(2 + √2).
- Expand and simplify (√7 + 3)(√7 − 3).
Open worked solutions — Exercise B
1. √12 × √27 = √324 = 18.
2. 3√5 × 2√10 = 6√50 = 30√2.
3. √147 ÷ √3 = √49 = 7.
4. (3 + √2)(2 + √2) = 6 + 3√2 + 2√2 + 2 = 8 + 5√2.
5. (√7 + 3)(√7 − 3) = 7 − 9 = −2.
Exercise C: Rationalising Denominators
- Rationalise 7/√2.
- Rationalise 5/√3.
- Rationalise 2/(3 + √5).
- Rationalise 4/(√7 − 1).
- Express (1 + √2)/(1 − √2) in the form a + b√2.
Open worked solutions — Exercise C
1. (7/√2) × (√2/√2) = 7√2/2.
2. (5/√3) × (√3/√3) = 5√3/3.
3. Multiply by (3 − √5):
2(3 − √5)/(9 − 5) = (3 − √5)/2.
4. Multiply by (√7 + 1):
4(√7 + 1)/(7 − 1) = 2(√7 + 1)/3.
5. Multiply by (1 + √2):
(1 + √2)²/(1 − 2) = (3 + 2√2)/(−1).
Answer: −3 − 2√2. Thus a = −3 and b = −2.
Exercise D: Mixed Examination Questions
- Simplify √192 − 2√27 + √75.
- Evaluate (√3 + √2)².
- Express 6/(2 − √3) in the form a + b√3.
- Simplify (√5 + √2)(√5 − √2) + √45.
- Given that x = √12 + √27, express x in its simplest surd form.
Open worked solutions — Exercise D
1. √192 = 8√3, 2√27 = 6√3 and √75 = 5√3.
Therefore 8√3 − 6√3 + 5√3 = 7√3.
2. (√3 + √2)² = 3 + 2√6 + 2 = 5 + 2√6.
3. Multiply by (2 + √3):
6(2 + √3)/(4 − 3) = 12 + 6√3.
4. (√5 + √2)(√5 − √2) = 5 − 2 = 3.
√45 = 3√5. Answer: 3 + 3√5.
5. √12 + √27 = 2√3 + 3√3 = 5√3.
13. Lesson Summary
- A surd is an irrational root expressed exactly in root form.
- Extract perfect-square factors to simplify surds.
- Only like surds can be added or subtracted.
- Multiply and divide surds using the ordinary laws of roots.
- Expand brackets using the distributive law.
- Use conjugates to rationalise binomial denominators.
- Always simplify the final answer fully.
MATHEMATICS HIPHOP
Making Mathematics Easier, One Concept at a Time.
Keep practising. Understand every step. Build mathematical confidence.
Coming Next: Chapter 09 — Powers, Part 4: Further Applications of Surds and Rationalisation.
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